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Class 10 · Science

Electricity: current, resistance and power

Revise Ohm’s law, series and parallel resistance, electrical power and energy units.

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Electric current is the rate of flow of charge: I = Q/t. Potential difference is energy transferred per unit charge: V = W/Q. The units are ampere for current, coulomb for charge and volt for potential difference. Keep symbols and units visible throughout a calculation.

Ohm’s law and combinations

For an ohmic conductor under constant physical conditions, V = IR. Resistance R is measured in ohms, Ω. If temperature or other physical conditions change substantially, do not assume the same resistance or a linear V–I relationship.

For resistors in series, R = R₁ + R₂ + … and the current through each is the same. In parallel, 1/R = 1/R₁ + 1/R₂ + … and the potential difference across each branch is the same.

  • A series equivalent resistance exceeds any single positive resistor in the chain.
  • A parallel equivalent resistance is smaller than the smallest positive branch resistance.

Power and energy

Electrical power P = VI. For a resistor obeying V = IR, this also gives P = I²R = V²/R. Power is measured in watts. Energy transferred over a time t is E = Pt; watts multiplied by seconds give joules.

A kilowatt-hour is a unit of energy, not power. 1 kWh = 3.6 × 10⁶ J. Convert watts to kilowatts before multiplying by a time in hours to calculate kWh.

  • Use circuit questions for practice; never experiment with household mains wiring.

Put it into practice

A worked example

A 3 Ω resistor has 6 V across it. Find its current and power.

  1. I = V/R = 6/3 = 2 A.
  2. P = VI = 6 × 2 = 12 W.
  3. Check with I²R = 2² × 3 = 12 W.

Answer: Current = 2 A; power = 12 W.

Try it yourself

Have a go before revealing the answer.

  1. Find the equivalent resistance of 6 Ω and 3 Ω in parallel.

    Show answer

    1/R = 1/6 + 1/3 = 1/2, so R = 2 Ω.

    Answer: 1/R = 1/6 + 1/3 = 1/2, so R = 2 Ω.

  2. A 100 W device runs for five hours. How much energy does it use?

    Show answer

    0.1 kW × 5 h = 0.5 kWh.

    Answer: 0.1 kW × 5 h = 0.5 kWh.

Watch out for these

  • Do not add resistances directly when the resistors are in parallel.
  • kW is power; kWh is energy.

Continue with official resources

Match these concept notes to your current textbook and syllabus. They are independent explanations, not official board publications.